linear search program in c++

Linear search program in C

#include <stdio.h>

int main()
{
  int array[100], search, c, n;

  printf("Enter number of elements in array\n");
  scanf("%d", &n);

  printf("Enter %d integer(s)\n", n);

  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);

  printf("Enter a number to search\n");
  scanf("%d", &search);

  for (c = 0; c < n; c++)
  {
    if (array[c] == search)    /* If required element is found */
    {
      printf("%d is present at location %d.\n", search, c+1);
      break;
    }
  }
  if (c == n)
    printf("%d isn't present in the array.\n", search);

  return 0;
}

Linear search C program for multiple occurrences

In the code below we will print all locations at which required element is found and also the number of times it occurs in the list.

#include <stdio.h>
 
int main()
{
   int array[100], search, c, n, count = 0;
   
   printf("Enter number of elements in array\n");
   scanf("%d", &n);
   
   printf("Enter %d numbers\n", n);
   
   for (c = 0; c < n; c++)
      scanf("%d", &array[c]);
     
   printf("Enter a number to search\n");
   scanf("%d", &search);
   
   for (c = 0; c < n; c++) {
      if (array[c] == search) {
         printf("%d is present at location %d.\n", search, c+1);
         count++;
      }
   }
   if (count == 0)
      printf("%d isn't present in the array.\n", search);
   else
      printf("%d is present %d times in the array.\n", search, count);
     
   return 0;
}